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Assignment, Engineering and Construction Strength of materials- torsion

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    i will attach the questions

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    C&ENVENG 2025
    Strength of Materials IIA
    Semester 1, 2014
    Assignment 2: Torsion
    Due: 4pm Monday, 7 April 2014
    The assignment should be done by students individua
    lly. Solution should start with a clear statement o
    f the
    problem, a summary of the given information, what i
    s to be solved for, and then a clear and easy to fo
    llow
    solution with diagrams where appropriate and highli
    ghting any assumptions made along the way. If you b
    elieve
    that a parameter or an important piece of informati
    on has been inadvertently omitted, assume a suitabl
    e value,
    clearly stating it, and continue with the solution.
    Each question will be marked using criteria as sho
    wn below

    Correct working and answer: 100% mark

    Correct working but wrong answer (including wrong u
    nit): 70% mark

    Incorrect working and answer but demonstrate a cert
    ain level of understanding: 30% mark

    Incorrect working and answer, and demonstrate no un
    derstanding: 0% mark
    Assignment must be submitted to the course submissi
    on box in front of the School of Civil, Environment
    al &
    Mining Engineering Office (Eng. North N136). Late s
    ubmission will be penalised at the rate of 10% per
    day
    until the assignments are returned within a week. N
    o credit will be given for assignments submitted af
    ter they
    have been marked and returned to the class.
    Question 1 (30 marks total)
    While an oil well is being drilled at a depth of 20
    00m, it is observed that the top of the 20cm-diamet
    er steel drill
    pipe rotates though two complete revolutions before
    the drilling bit starts to rotate. Using G=90GPa,
    determine
    the maximum shearing stress in the pipe caused by t
    orsion.
    2000m
    Page
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    Question 2 (70 marks total)
    (a)
    From the torsion test 1 video (torsion test, small
    strain in “Course Material / Videos of experiments”
    ),
    calculate the shear modulus G of the steel material
    of the specimen.
    The specimen is made of structural steel with Young
    modulus E=200 GPa and Poisson’s ratio
    ?
    =0.3. Use
    the relationship between E and
    ?
    (see slide 29, Ch02_Stress_strain), determine G an
    d compare it with the
    value that you have just calculated above. What cau
    ses the difference in your opinion?
    Note:

    Use the incremental relationship
    ?
    t
    =
    ?
    ?
    G for the calculation of shear modulus G. This is
    due to the
    rigid body rotation (very small torque and large ro
    tation at the beginning of the test) of the specime
    n
    before the torsion loading taking effects. See figu
    re below.

    Cross section is circular with an averaged diameter
    determined from 3 measurements.
    (b)
    From the torsion test 2 video (torsion test, large
    strain), determine the shear stress at yield
    t
    y
    and estimate
    the ultimate shear stress
    t
    ult
    (assuming the whole cross section reaches the same
    ultimate stress). Same
    length L and averaged diameter in (a) can be used.
    Use the above material properties (shear modulus G,
    shear yield stress
    t
    y
    )
    for the design of steel rods under torsion:
    (c)
    For a solid cross section, determine the diameter d
    of the steel rod so that
    the maximum shear stress in the rod is equal to
    t
    y
    . Calculate the angle of
    twist at H.
    (d)
    To save material, a hollow circular cross section i
    s used. Given the inner
    radius c
    1
    =6mm, determine the outer radius c
    2
    so that the angle of twist at
    H does not exceed that calculated above in (c) AND
    the material does not yield. How much (in terms of
    material volume) can be saved compared to (c)?
    (e)
    Find the inner radius c
    1
    and outer radius c
    2
    of a hollow tube so that when subjected to the abo
    ve torque of
    250 Nm (Figure above):

    the angle of twist is equal to that calculated in (
    c)

    and the maximum stress in the tube is equal to the
    yield stress
    t
    y
    .
    length L on which rotation
    angle
    f
    (or angle of twist)
    is measured
    ?
    t
    and
    ?
    ?
    to be calculated from corresponding
    ?
    T
    (Torque) and
    ?
    f
    (Rotation)
    based on 2 points on the
    red dashed line.
    1.5m
    d
    250 Nm
    Question 2
    H